What is the derivative of sqrt(2x^2) ?

The derivative of sqrt(2x^2) is square root of 2

What is the first derivative of sqrt(2x^2) ?

The first derivative of sqrt(2x^2) is square root of 2

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\frac{d}{d x} (2 x^{2})

2

Solution steps

\frac{d}{d x} (2 x^{2})

Apply the chain rule:

\frac{1}{2 2 x ^{2}} \frac{d}{d x} (2 x^{2})

= \frac{1}{2 2 x ^{2}} \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (2 x^{2}) = 4 x

= \frac{1}{2 2 x ^{2}} \cdot 4 x

Simplify

\frac{1}{2 2 x ^{2}} \cdot 4 x : 2

= 2

f (x) = 7 ln (3)

\int sec (x) \cdot tan^{2} (x) d x

\int_{l n (4)}^{l n (16)} e^{\frac{x}{2}} d x

3 x e^{- 2 x}

G (r) = r + 7 r

What is the derivative of sqrt(2x^2) ?
The derivative of sqrt(2x^2) is square root of 2
What is the first derivative of sqrt(2x^2) ?
The first derivative of sqrt(2x^2) is square root of 2