What is the derivative of G(r)=sqrt(r)+\sqrt[7]{r} ?

The derivative of G(r)=sqrt(r)+\sqrt[7]{r} is 1/(2sqrt(r))+1/(7r^{6/7)}

What is the first derivative of G(r)=sqrt(r)+\sqrt[7]{r} ?

The first derivative of G(r)=sqrt(r)+\sqrt[7]{r} is 1/(2sqrt(r))+1/(7r^{6/7)}

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derivative of

G (r) = r + 7 r

\frac{1}{2 r} + \frac{1}{7 r ^{\frac{6}{7}}}

Solution steps

\frac{d}{d r} (r + 7 r)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d r} (r) + \frac{d}{d r} (7 r)

\frac{d}{d r} (r) = \frac{1}{2 r}

\frac{d}{d r} (7 r) = \frac{1}{7 r ^{\frac{6}{7}}}

= \frac{1}{2 r} + \frac{1}{7 r ^{\frac{6}{7}}}

\frac{d ^{5}}{d x ^{5}} (sin (x))

x \cdot x

\int 5 + 8 x d x

3 x - 8 y x^{2} + 1 \frac{d y}{d x} = 0, y (0) = 6

\int \frac{x - 3}{x ^{2} + 4 x + 8} d x

What is the derivative of G(r)=sqrt(r)+\sqrt[7]{r} ?
The derivative of G(r)=sqrt(r)+\sqrt[7]{r} is 1/(2sqrt(r))+1/(7r^{6/7)}
What is the first derivative of G(r)=sqrt(r)+\sqrt[7]{r} ?
The first derivative of G(r)=sqrt(r)+\sqrt[7]{r} is 1/(2sqrt(r))+1/(7r^{6/7)}