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Popular >

y^'+8y-6=0

Solution

y^{^{'}} + 8 y - 6 = 0

Solution

y = \frac{e ^{- 8 t - c_{1}}}{4} + \frac{3}{4}

Solution steps

y^{'} (t) + 8 y - 6 = 0

Solve separable ODE:

y = \frac{e ^{- 8 t - c_{1}}}{4} + \frac{3}{4}

y = \frac{e ^{- 8 t - c_{1}}}{4} + \frac{3}{4}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'+8y-6=0 ?
The solution for y^'+8y-6=0 is y=(e^{-8t-c_{1}})/4+3/4