What is the integral from 0 to infinity of e^{-4t} ?

The integral from 0 to infinity of e^{-4t} is 1/4

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integral from 0 to infinity of e^{-4t}

\int_{0}^{\infty} e^{- 4 t} d t

\frac{1}{4}

Decimal

0.25

Solution steps

\int_{0}^{\infty} e^{- 4 t} d t

Compute the indefinite integral:

\int e^{- 4 t} d t = - \frac{1}{4} e^{- 4 t} + C

Compute the boundaries:

\int_{0}^{\infty} e^{- 4 t} d t = 0 - (- \frac{1}{4})

= 0 - (- \frac{1}{4})

Simplify

= \frac{1}{4}

π^{4}

x \to \infty lim (x - 2)

x^{^{'}} = x (1 - x)

\frac{d}{d x} (- \frac{4 x - 3}{( 2 x ^{2} - 3 x - 5 ) ^{2}})

\frac{d x}{d y} = - \frac{4 y}{x}

What is the integral from 0 to infinity of e^{-4t} ?
The integral from 0 to infinity of e^{-4t} is 1/4