What is (\partial)/(\partial x)(7yzln(x)) ?

The answer to (\partial)/(\partial x)(7yzln(x)) is (7yz)/x

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(\partial)/(\partial x)(7yzln(x))

\frac{\partial}{\partial x} (7 yz ln (x))

\frac{7 yz}{x}

Solution steps

\frac{\partial}{\partial x} (7 yz ln (x))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 yz \frac{\partial}{\partial x} (ln (x))

Apply the common derivative:

\frac{\partial}{\partial x} (ln (x)) = \frac{1}{x}

= 7 yz \frac{1}{x}

Simplify

7 yz \frac{1}{x} : \frac{7 yz}{x}

= \frac{7 yz}{x}

y = \frac{3}{x}, (1, 3)

\int t^{5} - 5 t d t

y^{^{'''}} - y = 0

\int \frac{x}{2 + 2 x ^{2}} d x

\frac{1 + x}{4 - x}

What is (\partial)/(\partial x)(7yzln(x)) ?
The answer to (\partial)/(\partial x)(7yzln(x)) is (7yz)/x