What is derivative of y(θ)=θcos(θ) ?

The answer to derivative of y(θ)=θcos(θ) is (dy}{dx}=\frac{cos(x)-xsin(x)-y)/x

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derivative of y(θ)=θcos(θ)

derivative of

y = x cos (x)

\frac{d y}{d x} = \frac{cos ( x ) - x sin ( x ) - y}{x}

Solution steps

y x = x cos (x)

Treat

y

y (x)

Differentiate both sides:

x \frac{d y}{d x} + y = cos (x) - x sin (x)

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{cos ( x ) - x sin ( x ) - y}{x}

\frac{d y}{d x} = \frac{cos ( x ) - x sin ( x ) - y}{x}

6 x sin (x^{2})

y = 1 - x^{2}, y = x^{2} - 1

y^{^{''}} + 3 y^{^{'}} - 12 y = 0

y = \frac{- 13}{3 x}

\int x sin (x^{\frac{3}{2}} + 1) d x

What is derivative of y(θ)=θcos(θ) ?
The answer to derivative of y(θ)=θcos(θ) is (dy}{dx}=\frac{cos(x)-xsin(x)-y)/x