What is the integral from 0 to 3 of 1/((x+2)^4) ?

The integral from 0 to 3 of 1/((x+2)^4) is 39/1000

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integral from 0 to 3 of 1/((x+2)^4)

\int_{0}^{3} \frac{1}{( x + 2 ) ^{4}} d x

\frac{39}{1000}

Decimal

0.039

Solution steps

\int_{0}^{3} \frac{1}{( x + 2 ) ^{4}} d x

Apply u-substitution

: \int_{2}^{5} \frac{1}{u ^{4}} d u

= \int_{2}^{5} \frac{1}{u ^{4}} d u

Apply the Power Rule

: [- \frac{1}{3 u ^{3}}]_{2}^{5}

= [- \frac{1}{3 u ^{3}}]_{2}^{5}

Compute the boundaries:

\frac{39}{1000}

= \frac{39}{1000}

t \to 0 lim (\frac{e ^{- 2 t} - 1}{t})

\frac{\partial}{\partial x} (sin (x) y^{2})

\int \frac{1}{2 t ^{3}} d t

\frac{d}{d x} (3 x^{2} y^{3})

\frac{d}{d x} (x^{2} (2 x - 1)^{4})

What is the integral from 0 to 3 of 1/((x+2)^4) ?
The integral from 0 to 3 of 1/((x+2)^4) is 39/1000