What is the tangent of f(x)=sqrt(5x),(5,5) ?

The tangent of f(x)=sqrt(5x),(5,5) is y= 1/2 x+5/2

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tangent of f(x)=sqrt(5x),(5,5)

tangent of

f (x) = 5 x, (5, 5)

y = \frac{1}{2} x + \frac{5}{2}

Solution steps

Find the slope of

f (x) = 5 x : \frac{df ( x )}{d x} = \frac{5}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(5, 5) : y = \frac{1}{2} x + \frac{5}{2}

y = \frac{1}{2} x + \frac{5}{2}

x \to 2 lim ([x^{2} f (x)])

f (x) = - 3 x^{2}, at x = 1

5 x^{3} - 3 x^{5}

(x y^{2}) \frac{d y}{d x} = y^{3} - x^{3}

\int x^{2} x - 2 d x

What is the tangent of f(x)=sqrt(5x),(5,5) ?
The tangent of f(x)=sqrt(5x),(5,5) is y= 1/2 x+5/2