What is the derivative of 2x^{-4} ?

The derivative of 2x^{-4} is -8/(x^5)

What is the first derivative of 2x^{-4} ?

The first derivative of 2x^{-4} is -8/(x^5)

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\frac{d}{d x} (2 x^{- 4})

- \frac{8}{x ^{5}}

Solution steps

\frac{d}{d x} (2 x^{- 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 4 x^{- 4 - 1})

Simplify

2 (- 4 x^{- 4 - 1}) : - \frac{8}{x ^{5}}

= - \frac{8}{x ^{5}}

\int x^{3} ln (5 x) d x

(x^{2} e^{x})^{^{'}}

y^{^{'}} + \frac{2 y}{x} = - \frac{4}{x}

\int_{0}^{1} \frac{9 y}{e ^{2 y}} d y

\int sin (x) cos (y) d y

What is the derivative of 2x^{-4} ?
The derivative of 2x^{-4} is -8/(x^5)
What is the first derivative of 2x^{-4} ?
The first derivative of 2x^{-4} is -8/(x^5)