What is (\partial)/(\partial x)(-5cos(9x)) ?

The answer to (\partial)/(\partial x)(-5cos(9x)) is 45sin(9x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(-5cos(9x))

\frac{\partial}{\partial x} (- 5 cos (9 x))

45 sin (9 x)

Solution steps

\frac{\partial}{\partial x} (- 5 cos (9 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 5 \frac{\partial}{\partial x} (cos (9 x))

Apply the chain rule:

- sin (9 x) \frac{\partial}{\partial x} (9 x)

= - sin (9 x) \frac{\partial}{\partial x} (9 x)

\frac{\partial}{\partial x} (9 x) = 9

= - 5 (- sin (9 x) \cdot 9)

Simplify

= 45 sin (9 x)

(x^{2} + 1) \frac{d y}{d x} + 4 x (y - 1) = 0, y (0) = 6

y = 2 x + 4

7 x - 8 y x^{2} + 1 (\frac{d y}{d x}) = 0

\int 9 x + \frac{1}{9 x} d x

\frac{d ^{2} y}{d x ^{2}} - 4 y = 0, y (0) = 2

What is (\partial)/(\partial x)(-5cos(9x)) ?
The answer to (\partial)/(\partial x)(-5cos(9x)) is 45sin(9x)