What is the derivative of y=x^3+6 ?

The derivative of y=x^3+6 is 3x^2

What is the first derivative of y=x^3+6 ?

The first derivative of y=x^3+6 is 3x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = x^{3} + 6

3 x^{2}

Solution steps

\frac{d}{d x} (x^{3} + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (6)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6) = 0

= 3 x^{2} + 0

Simplify

= 3 x^{2}

\frac{s}{( s + 1 ) ( s + 2 )}

\frac{2}{s ^{2} + 6 s + 13}

3 sin (2 t + 5)

\frac{d}{d θ} (sec (θ))

\frac{y ^{^{'}} - ( x y )}{( 1 + x )} = x

What is the derivative of y=x^3+6 ?
The derivative of y=x^3+6 is 3x^2
What is the first derivative of y=x^3+6 ?
The first derivative of y=x^3+6 is 3x^2