What is the limit as x approaches 0 of (16)/(x^4) ?

The limit as x approaches 0 of (16)/(x^4) is infinity

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limit as x approaches 0 of (16)/(x^4)

x \to 0 lim (\frac{16}{x ^{4}})

\infty

Solution steps

x \to 0 lim (\frac{16}{x ^{4}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (\frac{16}{x ^{4}}) = \infty

x \to 0 + lim (\frac{16}{x ^{4}}) = \infty

= \infty

f (x) = \frac{1}{x + 6}

\frac{e ^{y} + e ^{- y}}{2}

\int e^{y^{2}} d y

\int \frac{10}{8 x - 4 x ^{2}} d x

\int_{\frac{1}{2}}^{\frac{e}{2}} ln (2 x) d x

What is the limit as x approaches 0 of (16)/(x^4) ?
The limit as x approaches 0 of (16)/(x^4) is infinity