What is the solution for (dy)/(dx)=(2y^4+x^4)/(xy^3) ?

The solution for (dy)/(dx)=(2y^4+x^4)/(xy^3) is y=x\sqrt[4]{-1+c_{1}x^4},y=-x\sqrt[4]{-1+c_{1}x^4}

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(dy)/(dx)=(2y^4+x^4)/(xy^3)

\frac{d y}{d x} = \frac{2 y ^{4} + x ^{4}}{x y ^{3}}

y = x 4 - 1 + c_{1} x^{4}, y = - x 4 - 1 + c_{1} x^{4}

Solution steps

\frac{d y}{d x} = \frac{2 y ^{4} + x ^{4}}{x y ^{3}}

Solve Bernoulli ODE:

y = x 4 - 1 + c_{1} x^{4}, y = - x 4 - 1 + c_{1} x^{4}

y = x 4 - 1 + c_{1} x^{4}, y = - x 4 - 1 + c_{1} x^{4}

\frac{d ^{3}}{d x ^{3}} (x^{5} e^{x})

\frac{d}{d x} (\frac{4 x ^{2}}{( 7 - 5 x ) ^{3}})

\int \frac{e ^{x}}{4 + e ^{2 x}} d x

\int t (t^{4} + t - 5) d t

\frac{\partial}{\partial x} (2 y - \frac{3}{y ^{2}} + x)

What is the solution for (dy)/(dx)=(2y^4+x^4)/(xy^3) ?
The solution for (dy)/(dx)=(2y^4+x^4)/(xy^3) is y=x\sqrt[4]{-1+c_{1}x^4},y=-x\sqrt[4]{-1+c_{1}x^4}