What is (\partial)/(\partial x)(2y-3/(y^2)+x) ?

The answer to (\partial)/(\partial x)(2y-3/(y^2)+x) is 1

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(\partial)/(\partial x)(2y-3/(y^2)+x)

\frac{\partial}{\partial x} (2 y - \frac{3}{y ^{2}} + x)

1

Solution steps

\frac{\partial}{\partial x} (2 y - \frac{3}{y ^{2}} + x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y) - \frac{\partial}{\partial x} (\frac{3}{y ^{2}}) + \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (\frac{3}{y ^{2}}) = 0

\frac{\partial}{\partial x} (x) = 1

= 0 - 0 + 1

Simplify

= 1

(x^{6} - 5) x

\frac{d}{d x} (\frac{cos ( x )}{x + 1})

\frac{d}{d x} (\frac{1}{x + k})

(x - 3) (x + 2) (x + 3)

\int x (x + 1) d x

What is (\partial)/(\partial x)(2y-3/(y^2)+x) ?
The answer to (\partial)/(\partial x)(2y-3/(y^2)+x) is 1