What is the derivative of 4x+sec^2(2x) ?

The derivative of 4x+sec^2(2x) is 4+4sec^2(2x)tan(2x)

What is the first derivative of 4x+sec^2(2x) ?

The first derivative of 4x+sec^2(2x) is 4+4sec^2(2x)tan(2x)

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\frac{d}{d x} (4 x + sec^{2} (2 x))

4 + 4 sec^{2} (2 x) tan (2 x)

Solution steps

\frac{d}{d x} (4 x + sec^{2} (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) + \frac{d}{d x} (sec^{2} (2 x))

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (sec^{2} (2 x)) = 4 sec^{2} (2 x) tan (2 x)

= 4 + 4 sec^{2} (2 x) tan (2 x)

\frac{7 x ^{2} + 5 x + 3}{x}

y^{^{''}} + 9 y = cos (10 t)

\frac{d}{d x} (\frac{sin ( x )}{x + tan ( x )})

\frac{\partial}{\partial x} (\frac{3}{t})

\int \frac{3}{x - 2} d x

What is the derivative of 4x+sec^2(2x) ?
The derivative of 4x+sec^2(2x) is 4+4sec^2(2x)tan(2x)
What is the first derivative of 4x+sec^2(2x) ?
The first derivative of 4x+sec^2(2x) is 4+4sec^2(2x)tan(2x)