What is the solution for x^2y^{''}+0y^'-2y=x^2 ?

The solution for x^2y^{''}+0y^'-2y=x^2 is y=c_{1}x^2+(c_{2})/x+1/3 x^2ln(x)-(x^2)/9

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x^2y^{''}+0y^'-2y=x^2

x^{2} y^{^{''}} + 0 y^{^{'}} - 2 y = x^{2}

y = c_{1} x^{2} + \frac{c _{2}}{x} + \frac{1}{3} x^{2} ln (x) - \frac{x ^{2}}{9}

Solution steps

x^{2} y^{''} (x) + 0 y^{'} (x) - 2 y = x^{2}

Solve linear ODE:

y = c_{1} x^{2} + \frac{c _{2}}{x} + \frac{1}{3} x^{2} ln (x) - \frac{x ^{2}}{9}

y = c_{1} x^{2} + \frac{c _{2}}{x} + \frac{1}{3} x^{2} ln (x) - \frac{x ^{2}}{9}

y = \frac{x - 2}{x ^{2}}

f (x) = (x^{2} + 3)^{6}

x \to 3 lim (x^{2} - 1)

\int x (5 + 2 x)^{4} d x

\int (sec (2 x))^{2} d x

What is the solution for x^2y^{''}+0y^'-2y=x^2 ?
The solution for x^2y^{''}+0y^'-2y=x^2 is y=c_{1}x^2+(c_{2})/x+1/3 x^2ln(x)-(x^2)/9