What is the tangent of y=-5-8x^2,(5,-205) ?

The tangent of y=-5-8x^2,(5,-205) is y=-80x+195

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=-5-8x^2,(5,-205)

tangent of

y = - 5 - 8 x^{2}, (5, - 205)

y = - 80 x + 195

Solution steps

Find the slope of

y = - 5 - 8 x^{2} : \frac{d y}{d x} = - 16 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 80

Find the line with slope m=

- 80

and passing through

(5, - 205) : y = - 80 x + 195

y = - 80 x + 195

\frac{2}{1 - x}, 0

\frac{1}{1 + x ^{2}}, 0

\int_{0}^{1} x^{2} (2 x^{3} - 1)^{4} d x

\frac{d}{d x} (9 e^{2 x})

\frac{\partial}{\partial x} (x^{2} y^{0.5})

What is the tangent of y=-5-8x^2,(5,-205) ?
The tangent of y=-5-8x^2,(5,-205) is y=-80x+195