What is the derivative of (x+1(x+3)) ?

The derivative of (x+1(x+3)) is 2x+4

What is the first derivative of (x+1(x+3)) ?

The first derivative of (x+1(x+3)) is 2x+4

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\frac{d}{d x} ((x + 1) (x + 3))

2 x + 4

Solution steps

\frac{d}{d x} ((x + 1) (x + 3))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x + 1, g = x + 3

= \frac{d}{d x} (x + 1) (x + 3) + \frac{d}{d x} (x + 3) (x + 1)

\frac{d}{d x} (x + 1) = 1

\frac{d}{d x} (x + 3) = 1

= 1 \cdot (x + 3) + 1 \cdot (x + 1)

Simplify

1 \cdot (x + 3) + 1 \cdot (x + 1) : 2 x + 4

= 2 x + 4

\frac{( x + 1 )}{( 5 - x )}

t \to 1 lim (\frac{\frac{1}{t}}{t - 1})

\int 1 + (x^{2} - \frac{1}{4 x ^{2}})^{2} d x

\frac{d}{d x} (sin (2 x + π))

f (x) = 2 x^{2} + 3 x - 2

What is the derivative of (x+1(x+3)) ?
The derivative of (x+1(x+3)) is 2x+4
What is the first derivative of (x+1(x+3)) ?
The first derivative of (x+1(x+3)) is 2x+4