What is the sum from n=1 to infinity of n/(2n^3) ?

The sum from n=1 to infinity of n/(2n^3) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of n/(2n^3)

n = 1 \sum \infty \frac{n}{2 n ^{3}}

converges

Solution steps

n = 1 \sum \infty \frac{n}{2 n ^{3}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= \frac{1}{2} \cdot n = 1 \sum \infty \frac{n}{n ^{3}}

Cancel the common factor:

n

= \frac{1}{2} \cdot n = 1 \sum \infty \frac{1}{n ^{2}}

Apply p-Series Test:

converges

= \frac{1}{2} converges

= converges

\int \frac{ln ( x ^{3} )}{2 x} d x

f (x) = 2 x - 5 x^{2}, (- 4, - 78)

\int 2 \cdot cos (2 x) d x

\int e^{- p^{2}} d p

\int_{0}^{3} \frac{t}{3 + t ^{2}} d t

What is the sum from n=1 to infinity of n/(2n^3) ?
The sum from n=1 to infinity of n/(2n^3) is converges