What is the integral of e^{-p^2} ?

The integral of e^{-p^2} is (sqrt(pi))/2 \erf(p)+C

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integral of e^{-p^2}

\int e^{- p^{2}} d p

\frac{π}{2} erf (p) + C

Solution steps

\int e^{- p^{2}} d p

Use the nonelementary integral:

\int e^{- p^{2}} d p = \frac{π}{2} erf (p)

= \frac{π}{2} erf (p)

Add a constant to the solution

= \frac{π}{2} erf (p) + C

\int_{0}^{3} \frac{t}{3 + t ^{2}} d t

f (x) = 4^{x}, at x = 0

\frac{d}{d x} (- 3 cos (x) + 4 sin (x))

y^{^{'}} - \frac{y}{x} = - x e^{- x}

f (x) = ln (\frac{3}{2}) x^{8}

What is the integral of e^{-p^2} ?
The integral of e^{-p^2} is (sqrt(pi))/2 \erf(p)+C