What is the solution for (dy)/(dx)=3xcos(x^2) ?

The solution for (dy)/(dx)=3xcos(x^2) is y= 3/2 sin(x^2)+c_{1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=3xcos(x^2)

\frac{d y}{d x} = 3 x cos (x^{2})

y = \frac{3}{2} sin (x^{2}) + c_{1}

Solution steps

\frac{d y}{d x} = 3 x cos (x^{2})

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = 3 x cos (x^{2})

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 3 x cos (x^{2}) d x

\int 3 x cos (x^{2}) d x = \frac{3}{2} sin (x^{2}) + c_{1}

y = \frac{3}{2} sin (x^{2}) + c_{1}

\int \frac{3}{5 - 9 x ^{2}} d x

\int_{7}^{9} \frac{1}{x ^{2} - 25} d x

f (x) = \frac{1}{10} + x e^{- x}

\frac{0.6 t ^{2} - t + 3}{t ^{2} + 3}

\frac{d}{d x} (8 x - 1)

What is the solution for (dy)/(dx)=3xcos(x^2) ?
The solution for (dy)/(dx)=3xcos(x^2) is y= 3/2 sin(x^2)+c_{1}