What is the derivative of 12x^3cos(x^4) ?

The derivative of 12x^3cos(x^4) is 12(3x^2cos(x^4)-4x^6sin(x^4))

What is the first derivative of 12x^3cos(x^4) ?

The first derivative of 12x^3cos(x^4) is 12(3x^2cos(x^4)-4x^6sin(x^4))

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\frac{d}{d x} (12 x^{3} cos (x^{4}))

12 (3 x^{2} cos (x^{4}) - 4 x^{6} sin (x^{4}))

Solution steps

\frac{d}{d x} (12 x^{3} cos (x^{4}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 12 \frac{d}{d x} (x^{3} cos (x^{4}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3}, g = cos (x^{4})

= 12 (\frac{d}{d x} (x^{3}) cos (x^{4}) + \frac{d}{d x} (cos (x^{4})) x^{3})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (cos (x^{4})) = - sin (x^{4}) \cdot 4 x^{3}

= 12 (3 x^{2} cos (x^{4}) + (- sin (x^{4}) \cdot 4 x^{3}) x^{3})

Simplify

12 (3 x^{2} cos (x^{4}) + (- sin (x^{4}) \cdot 4 x^{3}) x^{3}) : 12 (3 x^{2} cos (x^{4}) - 4 x^{6} sin (x^{4}))

= 12 (3 x^{2} cos (x^{4}) - 4 x^{6} sin (x^{4}))

f (x) = \frac{2}{1 - 8 x}

\int \frac{y ^{2}}{2} d y

\frac{\partial}{\partial x} (\frac{1}{2} x^{2})

x \to 0 + lim (2 sin (x) ln (x))

y = x ln (x)

What is the derivative of 12x^3cos(x^4) ?
The derivative of 12x^3cos(x^4) is 12(3x^2cos(x^4)-4x^6sin(x^4))
What is the first derivative of 12x^3cos(x^4) ?
The first derivative of 12x^3cos(x^4) is 12(3x^2cos(x^4)-4x^6sin(x^4))