What is the tangent of f(x)=(1+4x)^9,(0,1) ?

The tangent of f(x)=(1+4x)^9,(0,1) is y=36x+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=(1+4x)^9,(0,1)

tangent of

f (x) = (1 + 4 x)^{9}, (0, 1)

y = 36 x + 1

Solution steps

Find the slope of

f (x) = (1 + 4 x)^{9} : \frac{df ( x )}{d x} = 36 (1 + 4 x)^{8}

Compute the slope of

f (x) = (1 + 4 x)^{9}

(0, 1) : m = 36

Find the line with slope m=

36

and passing through

(0, 1) : y = 36 x + 1

y = 36 x + 1

f (x) = - 3 (2 x - 2) = 0

\frac{d}{d x} (\frac{x ^{4}}{4} - 2 x^{2})

(0.1) (2)

\int 9 x cos (8 x) d x

y^{^{''}} + 4 y^{^{'}} = 0

What is the tangent of f(x)=(1+4x)^9,(0,1) ?
The tangent of f(x)=(1+4x)^9,(0,1) is y=36x+1