What is (\partial)/(\partial t)(rsin(t)sin(x)) ?

The answer to (\partial)/(\partial t)(rsin(t)sin(x)) is rsin(x)cos(t)

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(\partial)/(\partial t)(rsin(t)sin(x))

\frac{\partial}{\partial t} (r sin (t) sin (x))

r sin (x) cos (t)

Solution steps

\frac{\partial}{\partial t} (r sin (t) sin (x))

Treat

r, x

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= r sin (x) \frac{\partial}{\partial t} (sin (t))

Apply the common derivative:

\frac{\partial}{\partial t} (sin (t)) = cos (t)

= r sin (x) cos (t)

\frac{d}{d x} (e^{2 x - y})

\frac{d}{d y} (10 - 6 y + e^{- 3 x})

\int e^{- \frac{x}{20}} d x

\int \frac{4 + u}{u} d u

\frac{d}{d x} ((9 x^{4} + 5)^{3})

What is (\partial)/(\partial t)(rsin(t)sin(x)) ?
The answer to (\partial)/(\partial t)(rsin(t)sin(x)) is rsin(x)cos(t)