What is the derivative of 2+2cos(2x) ?

The derivative of 2+2cos(2x) is -4sin(2x)

What is the first derivative of 2+2cos(2x) ?

The first derivative of 2+2cos(2x) is -4sin(2x)

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\frac{d}{d x} (2 + 2 cos (2 x))

- 4 sin (2 x)

Solution steps

\frac{d}{d x} (2 + 2 cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (2 cos (2 x))

\frac{d}{d x} (2) = 0

\frac{d}{d x} (2 cos (2 x)) = - 4 sin (2 x)

= 0 - 4 sin (2 x)

Simplify

= - 4 sin (2 x)

\frac{d}{d x} (x^{4} - 1)

\int sec (θ) d θ

\int x arctan (18 x) d x

\int t sec^{2} (6 t) d t

n = 0 \sum \infty \frac{1}{1. 1 ^{n}}

What is the derivative of 2+2cos(2x) ?
The derivative of 2+2cos(2x) is -4sin(2x)
What is the first derivative of 2+2cos(2x) ?
The first derivative of 2+2cos(2x) is -4sin(2x)