What is the derivative of f(x)=3x+sqrt(x) ?

The derivative of f(x)=3x+sqrt(x) is 3+1/(2sqrt(x))

What is the first derivative of f(x)=3x+sqrt(x) ?

The first derivative of f(x)=3x+sqrt(x) is 3+1/(2sqrt(x))

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derivative of

f (x) = 3 x + x

3 + \frac{1}{2 x}

Solution steps

\frac{d}{d x} (3 x + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (x)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (x) = \frac{1}{2 x}

= 3 + \frac{1}{2 x}

\frac{d}{d x} (\frac{1}{2} x^{4} - 2 x^{2})

\frac{d}{d x} (ln (\frac{5 x + 1}{x ^{2} - 3}))

x \to 3 lim (\frac{x ^{3} - 9}{x - 3})

x^{3} + 2 x + 1, 1

\int \frac{x ^{7}}{7} - \frac{4 x ^{5}}{5} + \frac{x ^{2}}{2} + x + C d x

What is the derivative of f(x)=3x+sqrt(x) ?
The derivative of f(x)=3x+sqrt(x) is 3+1/(2sqrt(x))
What is the first derivative of f(x)=3x+sqrt(x) ?
The first derivative of f(x)=3x+sqrt(x) is 3+1/(2sqrt(x))