What is the derivative of f(x)=(11)/((2x^3-5)^4) ?

The derivative of f(x)=(11)/((2x^3-5)^4) is -(264x^2)/((2x^3-5)^5)

What is the first derivative of f(x)=(11)/((2x^3-5)^4) ?

The first derivative of f(x)=(11)/((2x^3-5)^4) is -(264x^2)/((2x^3-5)^5)

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derivative of

f (x) = \frac{11}{( 2 x ^{3} - 5 ) ^{4}}

- \frac{264 x ^{2}}{( 2 x ^{3} - 5 ) ^{5}}

Solution steps

\frac{d}{d x} (\frac{11}{( 2 x ^{3} - 5 ) ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 11 \frac{d}{d x} (\frac{1}{( 2 x ^{3} - 5 ) ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 11 \frac{d}{d x} ((2 x^{3} - 5)^{- 4})

Apply the chain rule:

- \frac{4}{( 2 x ^{3} - 5 ) ^{5}} \frac{d}{d x} (2 x^{3} - 5)

= - \frac{4}{( 2 x ^{3} - 5 ) ^{5}} \frac{d}{d x} (2 x^{3} - 5)

\frac{d}{d x} (2 x^{3} - 5) = 6 x^{2}

= 11 (- \frac{4}{( 2 x ^{3} - 5 ) ^{5}} \cdot 6 x^{2})

Simplify

11 (- \frac{4}{( 2 x ^{3} - 5 ) ^{5}} \cdot 6 x^{2}) : - \frac{264 x ^{2}}{( 2 x ^{3} - 5 ) ^{5}}

= - \frac{264 x ^{2}}{( 2 x ^{3} - 5 ) ^{5}}

\int \frac{3 x}{2 x + 4} d x

\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{9}{x ^{4}}) (x + 7 x^{3}))

x \to \infty + lim (a x^{2})

\frac{5}{12 s ^{2} + 7 s + 1}

sin (2 ln (x))

What is the derivative of f(x)=(11)/((2x^3-5)^4) ?
The derivative of f(x)=(11)/((2x^3-5)^4) is -(264x^2)/((2x^3-5)^5)
What is the first derivative of f(x)=(11)/((2x^3-5)^4) ?
The first derivative of f(x)=(11)/((2x^3-5)^4) is -(264x^2)/((2x^3-5)^5)