What is inverse oflaplace 5/(12s^2+7s+1) ?

The answer to inverse oflaplace 5/(12s^2+7s+1) is 5e^{-t/4}-5e^{-t/3}

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inverse oflaplace 5/(12s^2+7s+1)

inverse laplace

\frac{5}{12 s ^{2} + 7 s + 1}

5 e^{- \frac{t}{4}} - 5 e^{- \frac{t}{3}}

Solution steps

L^{- 1} {\frac{5}{12 s ^{2} + 7 s + 1}}

Take the partial fraction of

\frac{5}{12 s ^{2} + 7 s + 1} : \frac{20}{4 s + 1} - \frac{15}{3 s + 1}

= L^{- 1} {\frac{20}{4 s + 1} - \frac{15}{3 s + 1}}

Use the linearity property of Inverse Laplace Transform:

For functions

f (s), g (s)

and constants

a, b : L^{- 1} {a \cdot f (s) + b \cdot g (s)} = a \cdot L^{- 1} {f (s)} + b \cdot L^{- 1} {g (s)}

= L^{- 1} {\frac{20}{4 s + 1}} - L^{- 1} {\frac{15}{3 s + 1}}

L^{- 1} {\frac{20}{4 s + 1}} : 5 e^{- \frac{t}{4}}

L^{- 1} {\frac{15}{3 s + 1}} : 5 e^{- \frac{t}{3}}

= 5 e^{- \frac{t}{4}} - 5 e^{- \frac{t}{3}}

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What is inverse oflaplace 5/(12s^2+7s+1) ?
The answer to inverse oflaplace 5/(12s^2+7s+1) is 5e^{-t/4}-5e^{-t/3}