What is the integral from 2 to 3 of 1/(x^{2/3)} ?

The integral from 2 to 3 of 1/(x^{2/3)} is 3*3^{1/3}-3*2^{1/3}

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integral from 2 to 3 of 1/(x^{2/3)}

\int_{2}^{3} \frac{1}{x ^{\frac{2}{3}}} d x

3 \cdot 3^{\frac{1}{3}} - 3 \cdot 2^{\frac{1}{3}}

Decimal

0.54698 \dots

Solution steps

\int_{2}^{3} \frac{1}{x ^{\frac{2}{3}}} d x

Apply the Power Rule

: [3 x^{\frac{1}{3}}]_{2}^{3}

= [3 x^{\frac{1}{3}}]_{2}^{3}

Compute the boundaries:

3 \cdot 3^{\frac{1}{3}} - 3 \cdot 2^{\frac{1}{3}}

= 3 \cdot 3^{\frac{1}{3}} - 3 \cdot 2^{\frac{1}{3}}

\int 3 x^{2} 3 (5 x^{3} + 4)^{5} d x

\frac{d}{d x} (4 x^{\frac{5}{3}} - 3 x^{- 2} - 12)

2 3 x, at x = 1

\int_{0}^{1} x^{- \frac{1}{2}} d x

\frac{\partial}{\partial x} (\frac{x + 5}{y + 5})

What is the integral from 2 to 3 of 1/(x^{2/3)} ?
The integral from 2 to 3 of 1/(x^{2/3)} is 3*3^{1/3}-3*2^{1/3}