What is the derivative of y=5sec(5x) ?

The derivative of y=5sec(5x) is 25sec(5x)tan(5x)

What is the first derivative of y=5sec(5x) ?

The first derivative of y=5sec(5x) is 25sec(5x)tan(5x)

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derivative of

y = 5 sec (5 x)

25 sec (5 x) tan (5 x)

Solution steps

\frac{d}{d x} (5 sec (5 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (sec (5 x))

Apply the chain rule:

sec (5 x) tan (5 x) \frac{d}{d x} (5 x)

= sec (5 x) tan (5 x) \frac{d}{d x} (5 x)

\frac{d}{d x} (5 x) = 5

= 5 sec (5 x) tan (5 x) \cdot 5

Simplify

= 25 sec (5 x) tan (5 x)

(5.6) (5.9)

y = 3 x^{2} - x^{3}

(x + y)^{2} d x + (x + y)^{2} d y = 0

y = \frac{10}{x ^{2} - 4 x - 21}, x = - 2, x = 2

g (x) = x^{3} - 6 x^{2} + 9 x + 3

What is the derivative of y=5sec(5x) ?
The derivative of y=5sec(5x) is 25sec(5x)tan(5x)
What is the first derivative of y=5sec(5x) ?
The first derivative of y=5sec(5x) is 25sec(5x)tan(5x)