What is the derivative of f(x)=(x^2)/(x-5) ?

The derivative of f(x)=(x^2)/(x-5) is (x^2-10x)/((x-5)^2)

What is the first derivative of f(x)=(x^2)/(x-5) ?

The first derivative of f(x)=(x^2)/(x-5) is (x^2-10x)/((x-5)^2)

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derivative of

f (x) = \frac{x ^{2}}{x - 5}

\frac{x ^{2} - 10 x}{( x - 5 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{x - 5})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( x - 5 ) - \frac{d}{d x} ( x - 5 ) x ^{2}}{( x - 5 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x - 5) = 1

= \frac{2 x ( x - 5 ) - 1 \cdot x ^{2}}{( x - 5 ) ^{2}}

Simplify

\frac{2 x ( x - 5 ) - 1 \cdot x ^{2}}{( x - 5 ) ^{2}} : \frac{x ^{2} - 10 x}{( x - 5 ) ^{2}}

= \frac{x ^{2} - 10 x}{( x - 5 ) ^{2}}

\int \frac{1}{( x - 2 ) ( x - 3 ) ( x + 2 )} d x

\frac{d}{d x} (3 (8 x^{2} - 4 x)^{4})

f (x) = 12 x^{2}

\int \frac{e ^{2 x} - 1}{e ^{x} + e ^{- x}} d x

x \to - 6 - lim (tan (\frac{π x}{4}))

What is the derivative of f(x)=(x^2)/(x-5) ?
The derivative of f(x)=(x^2)/(x-5) is (x^2-10x)/((x-5)^2)
What is the first derivative of f(x)=(x^2)/(x-5) ?
The first derivative of f(x)=(x^2)/(x-5) is (x^2-10x)/((x-5)^2)