What is the derivative of \sqrt[3]{x-4} ?

The derivative of \sqrt[3]{x-4} is 1/(3(x-4)^{2/3)}

What is the first derivative of \sqrt[3]{x-4} ?

The first derivative of \sqrt[3]{x-4} is 1/(3(x-4)^{2/3)}

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\frac{d}{d x} (3 x - 4)

\frac{1}{3 ( x - 4 ) ^{\frac{2}{3}}}

Solution steps

\frac{d}{d x} (3 x - 4)

Apply the chain rule:

\frac{1}{3 ( x - 4 ) ^{\frac{2}{3}}} \frac{d}{d x} (x - 4)

= \frac{1}{3 ( x - 4 ) ^{\frac{2}{3}}} \frac{d}{d x} (x - 4)

\frac{d}{d x} (x - 4) = 1

= \frac{1}{3 ( x - 4 ) ^{\frac{2}{3}}} \cdot 1

Simplify

= \frac{1}{3 ( x - 4 ) ^{\frac{2}{3}}}

n = 0 \sum \infty \frac{1}{2} n

\int \frac{x ^{2} - x - 5}{x + 2} d x

\int (x^{2} + 3) e^{- x} d x

\int cos (k x) d x

2 x y^{^{'}} + y^{3} e^{- 2 x} = 2 x y

What is the derivative of \sqrt[3]{x-4} ?
The derivative of \sqrt[3]{x-4} is 1/(3(x-4)^{2/3)}
What is the first derivative of \sqrt[3]{x-4} ?
The first derivative of \sqrt[3]{x-4} is 1/(3(x-4)^{2/3)}