What is the derivative of 2/(\sqrt[4]{x}) ?

The derivative of 2/(\sqrt[4]{x}) is -1/(2x^{5/4)}

What is the first derivative of 2/(\sqrt[4]{x}) ?

The first derivative of 2/(\sqrt[4]{x}) is -1/(2x^{5/4)}

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\frac{d}{d x} (\frac{2}{4 x})

- \frac{1}{2 x ^{\frac{5}{4}}}

Solution steps

\frac{d}{d x} (\frac{2}{4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{4 x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} (x^{- \frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- \frac{1}{4} x^{- \frac{1}{4} - 1})

Simplify

2 (- \frac{1}{4} x^{- \frac{1}{4} - 1}) : - \frac{1}{2 x ^{\frac{5}{4}}}

= - \frac{1}{2 x ^{\frac{5}{4}}}

\frac{d}{d x} (8^{x} - 5^{x})

x \to 0 + lim ((4 x)^{\frac{4}{x}})

(- 8, 8), (1, - 10)

\frac{d}{d x} ((x + 3) I n x^{2})

\int (7 x - 6)^{4} d x

What is the derivative of 2/(\sqrt[4]{x}) ?
The derivative of 2/(\sqrt[4]{x}) is -1/(2x^{5/4)}
What is the first derivative of 2/(\sqrt[4]{x}) ?
The first derivative of 2/(\sqrt[4]{x}) is -1/(2x^{5/4)}