What is the solution for y^{''}+4pi^2y=0 ?

The solution for y^{''}+4pi^2y=0 is y=c_{1}cos(2pit)+c_{2}sin(2pit)

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y^{''}+4pi^2y=0

y^{^{''}} + 4 π^{2} y = 0

y = c_{1} cos (2 π t) + c_{2} sin (2 π t)

Solution steps

y^{''} (t) + 4 π^{2} y = 0

Solve linear ODE:

y = c_{1} cos (2 π t) + c_{2} sin (2 π t)

y = c_{1} cos (2 π t) + c_{2} sin (2 π t)

\frac{d}{d x} (2000 (1 + \frac{x}{12})^{60})

\frac{d}{d x} ((cos (5 x))^{x})

\int \frac{1}{16 x ^{2} + 1} d x

tan^{2} (x) + 1

y e^{x}

What is the solution for y^{''}+4pi^2y=0 ?
The solution for y^{''}+4pi^2y=0 is y=c_{1}cos(2pit)+c_{2}sin(2pit)