Solution
Solution
Solution steps
Apply Trigonometric Substitution
Take the constant out:
Use the common integral:
Substitute back
Simplify
Add a constant to the solution
Popular Examples
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Frequently Asked Questions (FAQ)
What is the integral of 1/(sqrt(16x^2+1)) ?
The integral of 1/(sqrt(16x^2+1)) is 1/4 ln|4x+sqrt(1+16x^2)|+C