What is (\partial)/(\partial x)(x^2-2xy+2y) ?

The answer to (\partial)/(\partial x)(x^2-2xy+2y) is 2x-2y

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(\partial)/(\partial x)(x^2-2xy+2y)

\frac{\partial}{\partial x} (x^{2} - 2 x y + 2 y)

2 x - 2 y

Solution steps

\frac{\partial}{\partial x} (x^{2} - 2 x y + 2 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (2 x y) + \frac{\partial}{\partial x} (2 y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (2 y) = 0

= 2 x - 2 y + 0

Simplify

= 2 x - 2 y

\frac{d}{d x} (k x^{x})

\frac{d}{d x} (\frac{x ^{2}}{( 4 + x )})

\frac{d}{d x} (\frac{3 x + 4}{3 x - 4})

y^{2} = x^{2} (x + 1), (3, 6)

\int x^{l n (x)} d x

What is (\partial)/(\partial x)(x^2-2xy+2y) ?
The answer to (\partial)/(\partial x)(x^2-2xy+2y) is 2x-2y