What is the derivative of x^2sin(3x) ?

The derivative of x^2sin(3x) is 2xsin(3x)+cos(3x)*3x^2

What is the first derivative of x^2sin(3x) ?

The first derivative of x^2sin(3x) is 2xsin(3x)+cos(3x)*3x^2

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derivative of

x^{2} sin (3 x)

2 x sin (3 x) + cos (3 x) \cdot 3 x^{2}

Solution steps

\frac{d}{d x} (x^{2} sin (3 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = sin (3 x)

= \frac{d}{d x} (x^{2}) sin (3 x) + \frac{d}{d x} (sin (3 x)) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (sin (3 x)) = cos (3 x) \cdot 3

= 2 x sin (3 x) + cos (3 x) \cdot 3 x^{2}

2 x sin (y) d x + x^{2} cos (y) d y = 0

\int - 24 x^{5} d x

\int (x^{2} + sec^{2} (x)) d x

n = 0 \sum \infty 0.7 4^{n}

x \to 3 lim (\frac{2 + x}{3 - x})

What is the derivative of x^2sin(3x) ?
The derivative of x^2sin(3x) is 2xsin(3x)+cos(3x)*3x^2
What is the first derivative of x^2sin(3x) ?
The first derivative of x^2sin(3x) is 2xsin(3x)+cos(3x)*3x^2