What is the integral from 0 to 0.6 of 200x ?

The integral from 0 to 0.6 of 200x is 36

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integral from 0 to 0.6 of 200x

\int_{0}^{0.6} 200 x d x

36

Solution steps

\int_{0}^{0.6} 200 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 200 \cdot \int_{0}^{0.6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.6}

= 200 [\frac{x ^{2}}{2}]_{0}^{0.6}

Simplify

= 200 [0.5 x^{2}]_{0}^{0.6}

Compute the boundaries:

0.18

= 200 \cdot 0.18

Simplify

= 36

\int tanh (\frac{x}{9}) d x

\frac{d}{d x} (e^{2 x} + sin (x^{2}))

\frac{d}{d x} (4 e^{3 x})

f (x) = (x^{3} + 2 x - 2)^{4}

3 e^{3 x} \frac{d y}{d x} = - 9 \frac{x}{y ^{2}}

What is the integral from 0 to 0.6 of 200x ?
The integral from 0 to 0.6 of 200x is 36