What is (\partial)/(\partial x)(2x-y) ?

The answer to (\partial)/(\partial x)(2x-y) is 2

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(\partial)/(\partial x)(2x-y)

\frac{\partial}{\partial x} (2 x - y)

2

Solution steps

\frac{\partial}{\partial x} (2 x - y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) - \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (y) = 0

= 2 - 0

Simplify

= 2

\int 2 x (x^{2} + 2)^{5} d x

\frac{d}{d x} (\frac{5 x}{4})

tan (x), 0

y^{^{'}} - y = 1, y (0) = 0

x \to 0 lim (x ln (x - 1))

What is (\partial)/(\partial x)(2x-y) ?
The answer to (\partial)/(\partial x)(2x-y) is 2