What is the integral from-2 to-1 of 1/x ?

The integral from-2 to-1 of 1/x is -ln(2)

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integral from-2 to-1 of 1/x

\int_{- 2}^{- 1} \frac{1}{x} d x

- ln (2)

Decimal

- 0.69314 \dots

Solution steps

\int_{- 2}^{- 1} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{- 2}^{- 1}

Compute the boundaries:

- ln (2)

= - ln (2)

\int_{- 1}^{1} x^{2} + 1 d x

f (x) = x^{2} - 2, at x = a

\int x^{2} sin (2 x) x d x

\int \frac{x + 1}{x ^{2} + 7 x + 10} d x

\int 12 - 8 x + x^{2} d x

What is the integral from-2 to-1 of 1/x ?
The integral from-2 to-1 of 1/x is -ln(2)