What is the derivative of 2x^2+7x^2+4x ?

The derivative of 2x^2+7x^2+4x is 18x+4

What is the first derivative of 2x^2+7x^2+4x ?

The first derivative of 2x^2+7x^2+4x is 18x+4

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derivative of

2 x^{2} + 7 x^{2} + 4 x

18 x + 4

Solution steps

\frac{d}{d x} (2 x^{2} + 7 x^{2} + 4 x)

Simplify

2 x^{2} + 7 x^{2} + 4 x : 9 x^{2} + 4 x

= \frac{d}{d x} (9 x^{2} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x^{2}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (9 x^{2}) = 18 x

\frac{d}{d x} (4 x) = 4

= 18 x + 4

\frac{d}{d x} (7 arcsin (x^{4}))

5 - x^{2}, 4 x^{2}

\frac{d}{d x} (ln (x^{- 3}))

y = \frac{8}{x ^{6}} - \frac{7}{x}

\int 13 sin^{2} (x) cos^{2} (x) d x

What is the derivative of 2x^2+7x^2+4x ?
The derivative of 2x^2+7x^2+4x is 18x+4
What is the first derivative of 2x^2+7x^2+4x ?
The first derivative of 2x^2+7x^2+4x is 18x+4