What is the derivative of y= 8/(x^6)-7/x ?

The derivative of y= 8/(x^6)-7/x is -(48)/(x^7)+7/(x^2)

What is the first derivative of y= 8/(x^6)-7/x ?

The first derivative of y= 8/(x^6)-7/x is -(48)/(x^7)+7/(x^2)

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derivative of

y = \frac{8}{x ^{6}} - \frac{7}{x}

- \frac{48}{x ^{7}} + \frac{7}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{8}{x ^{6}} - \frac{7}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{8}{x ^{6}}) - \frac{d}{d x} (\frac{7}{x})

\frac{d}{d x} (\frac{8}{x ^{6}}) = - \frac{48}{x ^{7}}

\frac{d}{d x} (\frac{7}{x}) = - \frac{7}{x ^{2}}

= - \frac{48}{x ^{7}} - (- \frac{7}{x ^{2}})

Simplify

= - \frac{48}{x ^{7}} + \frac{7}{x ^{2}}

\int 13 sin^{2} (x) cos^{2} (x) d x

\int \frac{1}{x ^{\frac{1}{4}}} d x

f (x) = 3 x^{2} - 5 x, at x = - 1

\frac{d}{d x} (\frac{x - x}{x ^{\frac{1}{3}}})

\frac{d y}{d x} - 2 y = + x^{2} + 5

What is the derivative of y= 8/(x^6)-7/x ?
The derivative of y= 8/(x^6)-7/x is -(48)/(x^7)+7/(x^2)
What is the first derivative of y= 8/(x^6)-7/x ?
The first derivative of y= 8/(x^6)-7/x is -(48)/(x^7)+7/(x^2)