What is the tangent of f(x)=3x^2-5x,\at x=-1 ?

The tangent of f(x)=3x^2-5x,\at x=-1 is y=-11x-3

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tangent of f(x)=3x^2-5x,\at x=-1

tangent of

f (x) = 3 x^{2} - 5 x, at x = - 1

y = - 11 x - 3

Solution steps

Find the tangent point:

(- 1, 8)

Find the slope of

f (x) = 3 x^{2} - 5 x : \frac{df ( x )}{d x} = 6 x - 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 11

Find the line with slope m=

- 11

and passing through

(- 1, 8) : y = - 11 x - 3

y = - 11 x - 3

\frac{d}{d x} (\frac{x - x}{x ^{\frac{1}{3}}})

\frac{d y}{d x} - 2 y = + x^{2} + 5

\frac{x ^{2}}{x ^{2} + 7}

\frac{d}{d x} (\frac{7 x}{x})

\frac{d}{d x} (x + ln (x + 1))

What is the tangent of f(x)=3x^2-5x,\at x=-1 ?
The tangent of f(x)=3x^2-5x,\at x=-1 is y=-11x-3