What is the derivative of x+ln(x+1) ?

The derivative of x+ln(x+1) is 1+1/(x+1)

What is the first derivative of x+ln(x+1) ?

The first derivative of x+ln(x+1) is 1+1/(x+1)

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\frac{d}{d x} (x + ln (x + 1))

1 + \frac{1}{x + 1}

Solution steps

\frac{d}{d x} (x + ln (x + 1))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (ln (x + 1))

\frac{d x}{d x} = 1

\frac{d}{d x} (ln (x + 1)) = \frac{1}{x + 1}

= 1 + \frac{1}{x + 1}

(1 + x^{4}) d y + x (1 + 4 y^{2}) d x = 0

\int 2 ln (3 x) d x

csc (5 x) cot (5 x)

\frac{7}{x}

\frac{\partial}{\partial z} (x^{2} + x y + y^{2} + 2 x - y)

What is the derivative of x+ln(x+1) ?
The derivative of x+ln(x+1) is 1+1/(x+1)
What is the first derivative of x+ln(x+1) ?
The first derivative of x+ln(x+1) is 1+1/(x+1)