What is the derivative of 2/(\sqrt[3]{x}+3cos(x)) ?

The derivative of 2/(\sqrt[3]{x}+3cos(x)) is -2/(3x^{4/3)}-3sin(x)

What is the first derivative of 2/(\sqrt[3]{x}+3cos(x)) ?

The first derivative of 2/(\sqrt[3]{x}+3cos(x)) is -2/(3x^{4/3)}-3sin(x)

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- \frac{2}{3 x ^{\frac{4}{3}}} - 3 sin (x)

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (3 cos (x)) = - 3 sin (x)

= - \frac{2}{3 x ^{\frac{4}{3}}} - 3 sin (x)

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\int (sec^{2} (x) tan (x)) d x

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ln (\frac{2 x + 1}{x ^{2} - 2})

\int \frac{4 x}{2 x + 1} d x

What is the derivative of 2/(\sqrt[3]{x}+3cos(x)) ?
The derivative of 2/(\sqrt[3]{x}+3cos(x)) is -2/(3x^{4/3)}-3sin(x)
What is the first derivative of 2/(\sqrt[3]{x}+3cos(x)) ?
The first derivative of 2/(\sqrt[3]{x}+3cos(x)) is -2/(3x^{4/3)}-3sin(x)