What is the (-6x-ln(1+6x)*(1+6x))^' ?

The (-6x-ln(1+6x)*(1+6x))^' is -6ln(6x+1)-12

What is the first (-6x-ln(1+6x)*(1+6x))^' ?

The first (-6x-ln(1+6x)*(1+6x))^' is -6ln(6x+1)-12

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(- 6 x - ln (1 + 6 x) \cdot (1 + 6 x))^{^{'}}

- 6 ln (6 x + 1) - 12

Solution steps

(- 6 x - ln (1 + 6 x) (1 + 6 x))^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - (6 x)^{^{'}} - (ln (1 + 6 x) (1 + 6 x))^{^{'}}

(6 x)^{'} = 6

(ln (1 + 6 x) (1 + 6 x))^{'} = 6 + 6 ln (1 + 6 x)

= - 6 - (6 + 6 ln (1 + 6 x))

Simplify

= - 6 ln (6 x + 1) - 12

n = 1 \sum \infty \frac{1}{n ^{3} + n ^{2}}

\frac{x ^{2} - 5 x + 3}{x ^{2} + 7}

f (x) = - 5 x^{2} + 2 x

f (x) = 5 x^{2} + 3

\frac{d}{d x} (\frac{3 sin ( x ) - 11 cos ( x )}{x - 2})

What is the (-6x-ln(1+6x)*(1+6x))^' ?
The (-6x-ln(1+6x)*(1+6x))^' is -6ln(6x+1)-12
What is the first (-6x-ln(1+6x)*(1+6x))^' ?
The first (-6x-ln(1+6x)*(1+6x))^' is -6ln(6x+1)-12