What is the derivative of f(x)=2x^2+3 ?

The derivative of f(x)=2x^2+3 is 4x

What is the first derivative of f(x)=2x^2+3 ?

The first derivative of f(x)=2x^2+3 is 4x

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derivative of

f (x) = 2 x^{2} + 3

4 x

Solution steps

\frac{d}{d x} (2 x^{2} + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3) = 0

= 4 x + 0

Simplify

= 4 x

\frac{d}{d x} (x^{(\frac{1}{3})})

f (x) = 10 x^{2} - 56 x + 104

\frac{d}{d x} (- \frac{1}{y - x})

\int \frac{x ^{2}}{( x + 2 ) ^{2} ( x + 4 ) ^{2}} d x

\int \frac{2 x}{x ^{2} - 2} d x

What is the derivative of f(x)=2x^2+3 ?
The derivative of f(x)=2x^2+3 is 4x
What is the first derivative of f(x)=2x^2+3 ?
The first derivative of f(x)=2x^2+3 is 4x