What is the derivative of f(x)=10x^2-56x+104 ?

The derivative of f(x)=10x^2-56x+104 is 20x-56

What is the first derivative of f(x)=10x^2-56x+104 ?

The first derivative of f(x)=10x^2-56x+104 is 20x-56

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derivative of

f (x) = 10 x^{2} - 56 x + 104

20 x - 56

Solution steps

\frac{d}{d x} (10 x^{2} - 56 x + 104)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (10 x^{2}) - \frac{d}{d x} (56 x) + \frac{d}{d x} (104)

\frac{d}{d x} (10 x^{2}) = 20 x

\frac{d}{d x} (56 x) = 56

\frac{d}{d x} (104) = 0

= 20 x - 56 + 0

Simplify

= 20 x - 56

\frac{d}{d x} (- \frac{1}{y - x})

\int \frac{x ^{2}}{( x + 2 ) ^{2} ( x + 4 ) ^{2}} d x

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\frac{d}{d x} (22 cos (x))

\frac{d}{d x} (- 2 cos (x) sin (x))

What is the derivative of f(x)=10x^2-56x+104 ?
The derivative of f(x)=10x^2-56x+104 is 20x-56
What is the first derivative of f(x)=10x^2-56x+104 ?
The first derivative of f(x)=10x^2-56x+104 is 20x-56