What is the derivative of-2cos(xsin(x)) ?

The derivative of-2cos(xsin(x)) is -cos(2x)*2

What is the first derivative of-2cos(xsin(x)) ?

The first derivative of-2cos(xsin(x)) is -cos(2x)*2

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\frac{d}{d x} (- 2 cos (x) sin (x))

- cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (- 2 cos (x) sin (x))

Simplify

- 2 cos (x) sin (x) : - sin (2 x)

= \frac{d}{d x} (- sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - cos (2 x) \cdot 2

y = (2 x - 1)^{5} (1 - x^{4})^{4}

\frac{2}{s \cdot ( s ^{2} + 4 s + 6 )}

\int 4 sin (2 x) + \frac{2 x ^{5} - x}{x} d x

\int \frac{x}{( 5 x ^{2} - 125 ) ^{\frac{1}{3}}} d x

y^{^{'}} = 0.0013 y (3000 - y)

What is the derivative of-2cos(xsin(x)) ?
The derivative of-2cos(xsin(x)) is -cos(2x)*2
What is the first derivative of-2cos(xsin(x)) ?
The first derivative of-2cos(xsin(x)) is -cos(2x)*2