What is the solution for y^'=0.0013y(3000-y) ?

The solution for y^'=0.0013y(3000-y) is y=(3.9)/(-e^{-3.89999…t-c_{1)}+0.0013}

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y^'=0.0013y(3000-y)

y^{^{'}} = 0.0013 y (3000 - y)

y = \frac{3.9}{- e ^{- 3.89999 \dots t - c_{1}} + 0.0013}

Solution steps

y^{'} (t) = 0.0013 y (3000 - y)

Solve Bernoulli ODE:

y = \frac{3.9}{- e ^{- 3.89999 \dots t - c_{1}} + 0.0013}

y = \frac{3.9}{- e ^{- 3.89999 \dots t - c_{1}} + 0.0013}

2 y^{^{'}} + 9 y = 3, y (0) = 1

x \to 0 - lim (- \frac{1}{x ^{2}})

\frac{d}{d x} ((x + 6) 2)

\int_{0}^{3} \frac{1}{x ^{2}} d x

f (x) = ln (x + 1)

What is the solution for y^'=0.0013y(3000-y) ?
The solution for y^'=0.0013y(3000-y) is y=(3.9)/(-e^{-3.89999…t-c_{1)}+0.0013}